UC知道(1-√2)^2+(√2-1)^2(√2-1)^2+(-√2-1)^2
来源：百度知道 编辑：UC知道 时间：2024/06/08 00:47:43
题目有错 应为(1-√2)^2+(√2＋1)^2(√2-1)^2+(-√2-1)^2
(1-√2)^2+(√2＋1)^2(√2-1)^2+(-√2-1)^2
=1-2√2+2+（2+1+2√2）（2+1-2√2）+2+1+2√2
=6+（4+2-4√2+2+1-2√2+4√2+2√2-8）
=6+6+3-8=7
个题目好像有点错了吧？
YS = (√2-1)^2+(√2-1)^2(√2-1)^2+(√2+1)^2
= (√2-1)^2(1+(√2-1)^2)+(3+2√2)
= (3-2√2)(4-2√2)+(3+2√2)
= (20-14√2)+(3+2√2)
= 23-12√2.
(√3+√2-1)(√3-√2+1)
(1-√2)^2+(√2-1)^2(√2-1)^2+(-√2-1)^2
计算：1/(√3 +√2) + 1/(√2+1) -2(√3 +1)
(1-√2)X^2=(1+√2)X
(1/√2+1+1/√3+√2...+1/√2008+√2007)*(√2008+1)
化简 √3+√2+1分之1 + √3+√2-1分之1......
(2+√2)÷ (2-√2)－1÷(√2-1)
计算1/1+√2+1/√2+√3+1/√3+√4+......+1/√n+√n+1
√(1-x) +√(x-1)+x ^2 -1=
(√3+1)^2001-2(√3+1)2000-2(√3+1)1999+2001